f(x+1)=5x^2+4x-10

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Solution for f(x+1)=5x^2+4x-10 equation: 


Simplifying
f(x + 1) = 5x2 + 4x + -10

Reorder the terms:
f(1 + x) = 5x2 + 4x + -10
(1 * f + x * f) = 5x2 + 4x + -10
(1f + fx) = 5x2 + 4x + -10

Reorder the terms:
1f + fx = -10 + 4x + 5x2

Solving
1f + fx = -10 + 4x + 5x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
10 + 1f + fx + -4x + -5x2 = -10 + 4x + 5x2 + 10 + -4x + -5x2

Reorder the terms:
10 + 1f + fx + -4x + -5x2 = -10 + 10 + 4x + -4x + 5x2 + -5x2

Combine like terms: -10 + 10 = 0
10 + 1f + fx + -4x + -5x2 = 0 + 4x + -4x + 5x2 + -5x2
10 + 1f + fx + -4x + -5x2 = 4x + -4x + 5x2 + -5x2

Combine like terms: 4x + -4x = 0
10 + 1f + fx + -4x + -5x2 = 0 + 5x2 + -5x2
10 + 1f + fx + -4x + -5x2 = 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
10 + 1f + fx + -4x + -5x2 = 0

The solution to this equation could not be determined.

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